Joshaline Douglas October 25, 2012 BIO 110 Punnet jog Journal 1. For angiotensin-converting enzyme of the monohybrid crosses you performed in this Investigation, specify how to use the phenotype ratios to lay the percentage of offspring displaying each trait. utilise a Punnett Square you gull (2X2 box) then an Ll across the go through and ll down the side. You pull up stakes then have Ll, Ll, ll, and ll. The lowercase letters interpret recessionary traits and the uppercase represent dominant. The ratios are split into Phenotypes and Genotypes. If you have at least one dominant trait then it is considered a genotype. For this problem Ll LL. ingeminate recessive is a phenotype (ll.) your ratio for the supra Ll, Ll, ll, ll is 2:4 (1:2) for both Phenotype and Genotype. 2. Can the genotype for a gray- personify drop be determined? Why or why not? diagnose totally of the possible genotypes for a locomote with that phenotype. Gray collective locomote woul d be dominant and raw bodied flies would be recessive. So, the results can only be a homozygous dominant vaporize (GG) or heterozygous fly (Gg). If I cross that fly with a dimmed bodied fly (gg) and there is a result of near black bodied flies, then you know the original fly was heterozygous.
If it results in all gray flies, then it was dominant. 3. Explain why an being with a homozygous dominant genotype has the uniform phenotype as an organism with a heterozygous genotype. Because the heterozygous has the aforementioned(prenominal) dominant that the homozygous does. Its only hybrid for another trait , still its dominance shows. 4. What! genetic reading can be obtained from a Punnett square? What genetic selective information cannot be determined from a Punnett square? Punnett squares are actually useful when dealing with rigorously dominant or strictly recessive genes. The resultant phenotype is understandably predictable.If you want to get a full essay, order it on our website: OrderCustomPaper.com
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